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20楼  发表于: 2007-11-02   
hehe
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21楼  发表于: 2007-11-02   
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22楼  发表于: 2007-11-02   
haha
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23楼  发表于: 2007-11-03   
在哪呢????
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24楼  发表于: 2007-11-07   
where
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25楼  发表于: 2007-11-09   
引用
引用第4楼鱼的自行车2007-10-31 09:56发表的“”: `Q>qmf_Fi  
努力为自己的梦想奋斗 ,大家加油
]==S?_.B3n  
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26楼  发表于: 2007-11-12   
没链接上吧
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27楼  发表于: 2007-11-12   
xiexie
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28楼  发表于: 2007-11-14   
看不到什么东西啊 edfb7prfTl  
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(1)       The center distance separability of a pair of involute spur cylindrical gears implies that a change in center distance does not affect the     . Ce@"+k+w  
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A. radii of the pitch circles     B. transmission ratio     C. working pressure angle .oe\wJS6  
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(2)       The main failure form of the closed gear drives with soft tooth surfaces is the       . FN D+Ok&  
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A. pitting of tooth surfaces     B. breaking of gear tooth =O~Y6|  
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C. wear of tooth surfaces     D. agglutination of tooth surfaces hJ*#t<.<P;  
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(3)       The tooth form factor in calculation of the bending fatigue strength of tooth root is independent of the       . ,o6,(jJU  
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A. tooth number   B. modification coefficient   C. module 8MBvp*  
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D. helix angle of helical gear *XluVochrb  
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(4)       The contact fatigue strength of tooth surfaces can be improved by way of     . &B} ,xcNO  
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A. adding module with not changing the diameter of reference circle ME'LZ"VT  
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B. increasing the diameter of reference circle \_t[\&.a}  
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C. adding tooth number with not changing the diameter of reference circle \-{2E  
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D. decreasing the diameter of reference circle fWl #CI\]  
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(5)       In design of cylindrical gear drives, b1 = b2 +(5~10)mm is recommended on purpose to       . (Where b1, b2 are the face widths of tooth of the smaller gear and the large gear respectively.) J''lOj(@  
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A. equalize strengths of the two gears         B. smooth the gear drive O\}w&BE:h  
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C. improve the contact strength of the smaller gear w,;ox2  
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D. compensate possible mounting error and ensure the length of contact line 9K=K,6 b  
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(6)       For a pair of involute spur cylindrical gears, if z1 < z2 , b1 > b2 , then     . t7,**$ST  
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A.     B.     C.     D. N'I9J?e Q  
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(7)       In a worm gear drive, the helix directions of the teeth of worm and worm gear are     the same. ,gIeQ!+vy  
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A. certainly       B. not always       C. certainly not {5JYu  
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(8)       Because of       , the general worm gear drives are not suitable for large power transmission. @Qd5a(5WM  
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A. the larger transmission ratios   B. the lower efficiency and the greater friction loss /n3SE0Y  
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C. the lower strength of worm gear   D. the slower rotating velocity of worm gear xhncQhf\  
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(9)       In a belt drive, if v1, v2 are the pitch circle velocities of the driving pulley and the driven pulley respectively, v is the belt velocity, then       . t CQf `  
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A.   B.   C.   D. gX/?  
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(10)   In a belt drive, if the smaller sheave is a driver, then the maximum stress of belt is located at the position of going     . k(_^Lq f-  
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A. into the driving sheave       B. into the driven sheave sUpSXG-W/@  
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C. out of the driving sheave       D. out of the driven sheave ^6 \@$   
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(11)   In a V-belt drive, if the wedge angle of V-belt is 40°,then the groove angle of V-belt sheaves should be     40°. `6o5[2V  
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A. greater than     B. equal to     C. less than     D. not less than 1"U.- I@  
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(12)   When the centerline of the two sheaves for a belt drive is horizontal, in order to increase the loading capacity, the preferred arrangement is with the       on top. / (Ryh6M  
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A. slack side   B. tight side BU=Ta$#BZ  
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(13)   In order to     , the larger sprocket should normally have no more than 120 teeth. USbFUHdDc  
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A. reduce moving nonuniformity of a chain drive kl#) 0yqN0  
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B. ensure the strength of the sprocket teeth     C. limit the transmission ratio JO\KTWtjO  
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D. reduce the possibility that the chain falls off from the sprockets due to wear out of the  ie <m)  
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chain $ZnVs@:S  
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(14)   In order to reduce velocity nonuniformity of a chain drive, we should take       . ?,FL"ye  
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A. the less z1 and the larger p     B. the more z1 and the larger p u1/q8'RW  
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C. the less z1 and the smaller p     D. the more z1 and the smaller p }xytV5a^  
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(Where z1 is the tooth number of the smaller sprocket, p is the chain pitch) 'jBtBFzP-  
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(15)   In design of a chain drive, the pitch number of the chain should be     . _OR[RGy  
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A. even number   B. odd number   C. prime number Ct}rj-L<i  
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D. integral multiple of the tooth number of the smaller sprocket lu V_  
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2. (6 points) Shown in the figure is the simplified fatigue limit stress diagram of an element. [300F=R  
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If the maximum working stress of the element is 180MPa, the minimum working stress is -80MPa. Find the angle q between the abscissa and the line connecting the working stress point to the origin. IR<*OnKn  
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3. (9 points) Shown in the figure is the translating follower velocity curve of a plate cam mechanism. u"M^qRhD  
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(1)   Draw acceleration curve of the follower schematically. %'<m[wf^ o  
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(2)   Indicate the positions where the impulses exist, and determine the types of the impulses (rigid impulse or soft impulse). zd#/zUPI  
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(3)   For the position F, determine whether the inertia force exists on the follower and whether the impulse exists. ~CL^%\K  
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4. (8 points) Shown in the figure is a pair of external spur involute gears.  a7UfRG  
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  The driving gear 1 rotates clockwise with angular velocity while the driven gear 2 rotates counterclockwise with angular velocity . , are the radii of the base circles. , are the radii of the addendum circles. , are the radii of the pitch circles. Label the theoretical line of action , the actual line of action , the working pressure angle and the pressure angles on the addendum circles , . (l3P<[[?  
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5. (10 points) For the elastic sliding and the slipping of belt drives, state briefly: 2!35Tj"RFE  
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(1)   the causes of producing the elastic sliding and the slipping. V5{^R+_)Ya  
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(2)   influence of the elastic sliding and the slipping on belt drives. !~&vcz0>)9  
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(3)   Can the elastic sliding and the slipping be avoided? Why? zU9G: jH  
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6. (10 points) A transmission system is as shown in the figure. Eo\# *Cv*  
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The links 1, 5 are worms. The links 2, 6 are worm gears. The links 3, 4 are helical gears. The links 7, 8 are bevel gears. The worm 1 is a driver. The rotation direction of the bevel gear 8 is as shown in the figure. The directions of the two axial forces acting on each middle axis are opposite. -vI?b#  
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(1)   Label the rotating direction of the worm 1. p2PD';"  
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(2)   Label the helix directions of the teeth of the helical gears 3, 4 and the worm gears 2, 6. -8qLshQ  
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7. (12 points) A planar cam-linkage mechanism is as shown in the figure with the working resistant force Q acting on the slider 4. Q <zL;AJ  
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  The magnitude of friction angle j (corresponding to the sliding pair and the higher pair) and the dashed friction circles (corresponding to all the revolute pairs) are as shown in the figure. The eccentric cam 1 is a driver and rotates clockwise. The masses of all the links are neglected. j*Q/vY!T  
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(1)   Label the action lines of the resultant forces of all the pairs for the position shown. iBxCk^  
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(2)   Label the rotation angle d of the cam 1 during which the point C moves from its highest position to the position shown in the figure. Give the graphing steps and all the graphical lines. I1kx3CwJ{P  
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8. (15 points) In the gear-linkage mechanism shown in the figure, the link 1 is a driver and rotates clockwise; the gear 4 is an output link. `BMg\2Ud*  
 #It{B  
(1)   Calculate the DOF of the mechanism and give the detailed calculating process. gx4`pH;B\  
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(2)   List the calculating expressions for finding the angular velocity ratios and for the position shown, using the method of instant centers. Determine the rotating directions of and . ! s?vj <  
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(3)   Replace the higher pair with lower pairs for the position shown. 9/{+,RpC  
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(4)   Disconnect the Assur groups from the mechanism and draw up their outlines. Determine the grade of each Assur group and the grade of the mechanism. /^DDU!=(<  
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9. (15 points) An offset crank-slider mechanism is as shown in the figure. ES;7_ .q  
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If the stroke of the slider 3 is H =500mm, the coefficient of travel speed variation is K =1.4, the ratio of the length of the crank AB to the length of the coupler BC is l = a/b =1/3. * Od_Cl  
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(1)   Find a, b, e (the offset).  w+=>b  
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(2)   If the working stroke of the mechanism is the slower stroke during which the slider 3 moves from its left limiting position to its right limiting position, determine the rotation direction of the crank 1. YKJk)%;+w  
VSx[{yn  
(3)   Find the minimum transmission angle gmin of the mechanism, and indicate the corresponding position of the crank 1.
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29楼  发表于: 2007-11-16   
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